Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Maths-

General

Easy

Question

The equation of the locus of a point which moves so as to be at equal distances from the point (a, 0) and the y-axis is

$y^{2} - 2 a x + a^{2} = 0$
$y^{2} + 2 a x + a^{2} = 0$
$x^{2} - 2 a y + a^{2} = 0$
$x^{2} + 2 a y + a^{2} = 0$

The correct answer is: $y to the power of 2 end exponent minus 2 a x plus a to the power of 2 end exponent equals 0$

As we know,
$left parenthesis h minus a right parenthesis to the power of 2 end exponent plus k to the power of 2 end exponent equals h to the power of 2 end exponent rightwards double arrow negative 2 a h plus a to the power of 2 end exponent plus k to the power of 2 end exponent equals 0$
On replacing (h, k) by (x, y), then $y to the power of 2 end exponent minus 2 a x plus a to the power of 2 end exponent equals 0$ is the required locus.

Related Questions to study

$text The curve end text 16 x to the power of 2 end exponent plus 8 x y plus y to the power of 2 end exponent minus 74 x minus 78 y plus 212 equals 0 text represents end text$

$text The curve end text 16 x to the power of 2 end exponent plus 8 x y plus y to the power of 2 end exponent minus 74 x minus 78 y plus 212 equals 0 text represents end text$

The axis of the parabola $x to the power of 2 end exponent minus 4 x minus 3 y plus 10 equals 0 text is end text$

The axis of the parabola $x to the power of 2 end exponent minus 4 x minus 3 y plus 10 equals 0 text is end text$

Focus and directrix of the parabola $x to the power of 2 end exponent equals negative 8 a y text are end text$

Focus and directrix of the parabola $x to the power of 2 end exponent equals negative 8 a y text are end text$

parallel

If the vertex of a parabola be at origin and directrix be x + = 5 0, then its latus rectum is

If the vertex of a parabola be at origin and directrix be x + = 5 0, then its latus rectum is

10th-Grade-Math---USA

125, 80, 140, 135, 126, 140, 350, 75
Maximum value of given data _______________

125, 80, 140, 135, 126, 140, 350, 75
Maximum value of given data _______________

10th-Grade-Math---USAGeneral

$S subscript N end subscript 1$ reaction is favoured by:

$S subscript N end subscript 1$ reaction is favoured by:

Chemistry-General

parallel

Order of base strength of the compounds :
I)
II)
III) $N H subscript 2 end subscript superscript minus end superscript$
IV)

Order of base strength of the compounds :
I)
II)
III) $N H subscript 2 end subscript superscript minus end superscript$
IV)

Chemistry-General

The stability of the following carbocation decreases in the order:
I)
II)
III)
IV)

The stability of the following carbocation decreases in the order:
I)
II)
III)
IV)

Chemistry-General

Which of the following orders is correct for the ease of electrophile addition on these alkenes?
I)
II)
III)

Which of the following orders is correct for the ease of electrophile addition on these alkenes?
I)
II)
III)

Chemistry-General

parallel

$capital delta$ H for CaCO₃(s) $⟶$ CaO(s) + CO₂(g) is 176 kJ mol^–1 at 1240 K. The $capital delta$ E for the change is equal to

$capital delta$ H for CaCO₃(s) $⟶$ CaO(s) + CO₂(g) is 176 kJ mol^–1 at 1240 K. The $capital delta$ E for the change is equal to

Chemistry-General

The heat evolved in combustion if 112 litres of water gas (mixture of equal volume of H₂(g) and CO(g) is
H₂(g) + 1/2 O₂(g) = H₂O(g) $capital delta$ H = –241.8 kJ
CO(g) + 1/2 O₂(g) = CO₂(g) $capital delta$ H = –283 kJ

The heat evolved in combustion if 112 litres of water gas (mixture of equal volume of H₂(g) and CO(g) is
H₂(g) + 1/2 O₂(g) = H₂O(g) $capital delta$ H = –241.8 kJ
CO(g) + 1/2 O₂(g) = CO₂(g) $capital delta$ H = –283 kJ

Chemistry-General

(1) For the given heat of reaction,
i) C(s) + O₂(g) = CO₂(g) + 97 kcal
ii) CO₂(g) + C(s) = 2CO(g) – 39 kcal the heat of combustion of CO(g) is:

(1) For the given heat of reaction,
i) C(s) + O₂(g) = CO₂(g) + 97 kcal
ii) CO₂(g) + C(s) = 2CO(g) – 39 kcal the heat of combustion of CO(g) is:

Chemistry-General

parallel

A solution of CuSO₄ is electrolysed using platinum inert electrodes. Due to electrolysis, the colour changes from blue to _ and pH of the solution .

A solution of CuSO₄ is electrolysed using platinum inert electrodes. Due to electrolysis, the colour changes from blue to _ and pH of the solution .

Chemistry-General

Chemistry-General

An electrophilic reagent is:

An electrophilic reagent is:

Chemistry-General

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.