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Maths-

General

Easy

Question

The equation $sin to the power of 2 end exponent invisible function application theta minus fraction numerator 4 over denominator sin to the power of 3 end exponent invisible function application theta minus 1 end fraction equals 1 minus fraction numerator 4 over denominator sin to the power of 3 end exponent invisible function application theta minus 1 end fraction$ has

No root
One root
Two roots
Infinite roots

The correct answer is: Infinite roots

$sin to the power of 2 end exponent invisible function application theta equals 1 open square brackets sin invisible function application theta not equal to 1 close square brackets$
$rightwards double arrow sin invisible function application theta equals negative 1 rightwards double arrow theta equals 2 n pi minus open parentheses pi divided by 2 close parentheses rightwards double arrow$ infinite roots

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