Maths-

General

Easy

Question

The equations of the sides of the Square for which (3, 4), (1, –1) are the end points of a diagonal are

7x+3y-33=0,3x-7y+19=0,3x-7y-10=0,7x+3y-4=0
6x+2y-31=0,2x-5y+18=0,2x-5y-5=0,2x+5y+1=0
x+y+5=0,x-y+2=0,5x+3y-11=0,5x+y-1=0
none of these

hint Hint:

find out the slope of the diagonal and find the slopes of the sides . then use the end points of the diagonal to calculate the equation of the sides.

The correct answer is: 7x+3y-33=0,3x-7y+19=0,3x-7y-10=0,7x+3y-4=0

3x-7y-19=0, 7x+3y-33=0 , 7x+3y-4=0, 3x – 7y -10=0

slope of the diagonal : (4-(-1))/ (3-1)
= 5/2
Angle made by the sides with the diagonals = 45 degree
Slope of the sides :
Tan 45 = |m-(5/2)|/|1+(5m/2)|
On solving we get
5m+2=±(2m-5)
m=-7/3 or 3/7
equation of sides :
y-y1=m(x-x1)
7x+3y-4=0
3x – 7y -10=0
Similarly, at (1,-1),
3x-7y-19=0
7x+3y-33=0

tan (x) = (m1-m2)/(1+m1m2). this gives the relationship between the slope and angle between the two line.

The figure shows energy levels of a certain atom, when the system moves from level 2E to E, a photon of wavelength $λ$ is emitted. The wavelength of photon produced during its transition from level 4/3 E to E level is:

physics-General

General

physics-

An α-Particle of energy 5 Mev is scattered through 180 $degree$ by a fixed uranium nuclear The closest distance is in the order of:

physics-General

General

chemistry-

Species having zero dipole moment:

chemistry-General

General

chemistry-

Which of the following process are associated with change of hybridization of the underlined compound?
1) Al(OH)₃ ppt. dissolved in NaOH
2) B2H₆ is dissolved in THF
3) SiF₄vapour is passed through liq. HF
4)Solidification PCl₅ vapour Correct answer is-

chemistry-General

General

chemistry-

The As F₅molecule is trigonal bipyramidal. The hybrid orbitals used by the As atoms for bonding-

chemistry-General

General

chemistry-

In [Fe(CO)₅], hybrid is at ion state and number of co-ordinate bonds are-

chemistry-General

General

Maths-

The condition that the equation $a x to the power of 2 end exponent plus 2 h x y plus b y to the power of 2 end exponent plus 2 g x plus 2 f y plus c equals 0$ can take the form $a x squared plus 2 h x y plus b y squared equals 0$ when shifting the origin is

When the roots are equal and real, then the discriminant value of the the quadratic equation becomes 0.

The condition that the equation $a x to the power of 2 end exponent plus 2 h x y plus b y to the power of 2 end exponent plus 2 g x plus 2 f y plus c equals 0$ can take the form $a x squared plus 2 h x y plus b y squared equals 0$ when shifting the origin is

Maths-General

When the roots are equal and real, then the discriminant value of the the quadratic equation becomes 0.

General

chemistry-

Compound with the highest melting point is-

chemistry-General

General

chemistry-

In the Born-Haber cycle for the formation of solid common salt (NaCl), the largest contribution comes from-

chemistry-General

General

chemistry-

Which of the following molecule is having complete octet-

chemistry-General

General

chemistry-

In a homonuclear molecule which of the following set of orbitals are degenerate?

chemistry-General

General

chemistry-

MolecularorbitalelectronicconfigurationofBe2, willbe-
a)KK, σ2s²
b)KK,σ2s²,σ2s²
c)σ1s²,σ1s²,σ2s²,σ2s²
d)σ1s²,σ1s²,σ2s²,2p²Correctansweris-

chemistry-General

Have a query? Ask a Tutor!!

Can’t find what you’re looking for?

The equations of the sides of the Square for which (3, 4), (1, –1) are the end points of a diagonal are

7x+3y-33=0,3x-7y+19=0,3x-7y-10=0,7x+3y-4=0 6x+2y-31=0,2x-5y+18=0,2x-5y-5=0,2x+5y+1=0 x+y+5=0,x-y+2=0,5x+3y-11=0,5x+y-1=0 none of these

find out the slope of the diagonal and find the slopes of the sides . then use the end points of the diagonal to calculate the equation of the sides.

The correct answer is: 7x+3y-33=0,3x-7y+19=0,3x-7y-10=0,7x+3y-4=0

Related Questions to study

The figure shows energy levels of a certain atom, when the system moves from level 2E to E, a photon of wavelength λ is emitted. The wavelength of photon produced during its transition from level 4/3 E to E level is:

The figure shows energy levels of a certain atom, when the system moves from level 2E to E, a photon of wavelength λ is emitted. The wavelength of photon produced during its transition from level 4/3 E to E level is:

An α-Particle of energy 5 Mev is scattered through 180 by a fixed uranium nuclear The closest distance is in the order of:

An α-Particle of energy 5 Mev is scattered through 180 by a fixed uranium nuclear The closest distance is in the order of:

Species having zero dipole moment:

Species having zero dipole moment:

Which of the following process are associated with change of hybridization of the underlined compound?1) Al(OH)3 ppt. dissolved in NaOH2) B2H6 is dissolved in THF3) SiF4 vapour is passed through liq. HF4)Solidification PCl5 vapour Correct answer is-

Which of the following process are associated with change of hybridization of the underlined compound?1) Al(OH)3 ppt. dissolved in NaOH2) B2H6 is dissolved in THF3) SiF4 vapour is passed through liq. HF4)Solidification PCl5 vapour Correct answer is-

The shapes of XeF4,XeF5–and SnCl2 are-

The shapes of XeF4,XeF5–and SnCl2 are-

Linear structure is assumed by-I)NCO–II) CS2III) NO2IV)Solid BeH

Linear structure is assumed by-I)NCO–II) CS2III) NO2IV)Solid BeH

Which of the following set is not correct-

Which of the following set is not correct-

The As F5 molecule is trigonal bipyramidal. The hybrid orbitals used by the As atoms for bonding-

The As F5 molecule is trigonal bipyramidal. The hybrid orbitals used by the As atoms for bonding-

In [Fe(CO)5], hybrid is at ion state and number of co-ordinate bonds are-

In [Fe(CO)5], hybrid is at ion state and number of co-ordinate bonds are-

The condition that the equation can take the form when shifting the origin is

The condition that the equation can take the form when shifting the origin is

Compound with the highest melting point is-

Compound with the highest melting point is-

In the Born-Haber cycle for the formation of solid common salt (NaCl), the largest contribution comes from-

In the Born-Haber cycle for the formation of solid common salt (NaCl), the largest contribution comes from-

Which of the following molecule is having complete octet-

Which of the following molecule is having complete octet-

In a homonuclear molecule which of the following set of orbitals are degenerate?

In a homonuclear molecule which of the following set of orbitals are degenerate?

MolecularorbitalelectronicconfigurationofBe2, willbe-a)KK, σ2s2b)KK,σ2s2,σ*2s2c)σ1s2,σ*1s2,σ2s2,σ*2s2d)σ1s2,σ*1s2,σ2s2,2p2Correctansweris-

MolecularorbitalelectronicconfigurationofBe2, willbe-a)KK, σ2s2b)KK,σ2s2,σ*2s2c)σ1s2,σ*1s2,σ2s2,σ*2s2d)σ1s2,σ*1s2,σ2s2,2p2Correctansweris-

With Turito Academy.

With Turito Foundation.

Get an Expert Advice From Turito.

Turito Academy

With Turito Academy.

Test Prep

With Turito Foundation.

Courses

Quick Links

7x+3y-33=0,3x-7y+19=0,3x-7y-10=0,7x+3y-4=0
6x+2y-31=0,2x-5y+18=0,2x-5y-5=0,2x+5y+1=0
x+y+5=0,x-y+2=0,5x+3y-11=0,5x+y-1=0
none of these

The figure shows energy levels of a certain atom, when the system moves from level 2E to E, a photon of wavelength $λ$ is emitted. The wavelength of photon produced during its transition from level 4/3 E to E level is:

The figure shows energy levels of a certain atom, when the system moves from level 2E to E, a photon of wavelength $λ$ is emitted. The wavelength of photon produced during its transition from level 4/3 E to E level is:

An α-Particle of energy 5 Mev is scattered through 180 $degree$ by a fixed uranium nuclear The closest distance is in the order of:

An α-Particle of energy 5 Mev is scattered through 180 $degree$ by a fixed uranium nuclear The closest distance is in the order of:

Which of the following process are associated with change of hybridization of the underlined compound?
1) Al(OH)₃ ppt. dissolved in NaOH
2) B2H₆ is dissolved in THF
3) SiF₄vapour is passed through liq. HF
4)Solidification PCl₅ vapour Correct answer is-

Which of the following process are associated with change of hybridization of the underlined compound?
1) Al(OH)₃ ppt. dissolved in NaOH
2) B2H₆ is dissolved in THF
3) SiF₄vapour is passed through liq. HF
4)Solidification PCl₅ vapour Correct answer is-

The shapes of XeF₄,XeF₅–and SnCl₂ are-

The shapes of XeF₄,XeF₅–and SnCl₂ are-

Linear structure is assumed by-
I)NCO^–
II) CS₂
III) NO₂
IV)Solid BeH

Linear structure is assumed by-
I)NCO^–
II) CS₂
III) NO₂
IV)Solid BeH

The As F₅molecule is trigonal bipyramidal. The hybrid orbitals used by the As atoms for bonding-

The As F₅molecule is trigonal bipyramidal. The hybrid orbitals used by the As atoms for bonding-

In [Fe(CO)₅], hybrid is at ion state and number of co-ordinate bonds are-

In [Fe(CO)₅], hybrid is at ion state and number of co-ordinate bonds are-

The condition that the equation $a x to the power of 2 end exponent plus 2 h x y plus b y to the power of 2 end exponent plus 2 g x plus 2 f y plus c equals 0$ can take the form $a x squared plus 2 h x y plus b y squared equals 0$ when shifting the origin is

The condition that the equation $a x to the power of 2 end exponent plus 2 h x y plus b y to the power of 2 end exponent plus 2 g x plus 2 f y plus c equals 0$ can take the form $a x squared plus 2 h x y plus b y squared equals 0$ when shifting the origin is

MolecularorbitalelectronicconfigurationofBe2, willbe-
a)KK, σ2s²
b)KK,σ2s²,σ2s²
c)σ1s²,σ1s²,σ2s²,σ2s²
d)σ1s²,σ1s²,σ2s²,2p²Correctansweris-

MolecularorbitalelectronicconfigurationofBe2, willbe-
a)KK, σ2s²
b)KK,σ2s²,σ2s²
c)σ1s²,σ1s²,σ2s²,σ2s²
d)σ1s²,σ1s²,σ2s²,2p²Correctansweris-