Maths-
General
Easy
Question
The normal to the curve x = 3 cos
–
, y = 3 sin
– 
at the point
=
/4 passes through the point -
- (2, –2)
- (0, 0)
- (–1, 1)
- None of these
Hint:
Find, Slope of tangent =
= 
Then find slope of normal, and substitute the values in equation of normal line.
The correct answer is: (0, 0)
Given :
x = 

At 

At P(
= 
Slope of tangent =
= 

= 
Slope of tangent at point P(
= 
When slope of tangent at P= -1
Slope of normal at point P = 1
Equation of normal at point P
y - y1 = m(x-x1)

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