Maths-
General
Easy
Question
The equation of the ellipse whose focus is (1, -1). directrix x – y – 3 = 0 and eccentricity is
- 7x2 + 2xy + 7y2 – 10x + 10y + 7 = 0
- 7x2 + 2xy + 7y2 = 7 = 0
- 7x2 + 2xy + 7y2 + 10x – 10y – 7 = 0
- none of these.
Hint:
The ratio of distances from the center of the ellipse from either focus to the semi-major axis of the ellipse is defined as the eccentricity of the ellipse.
The eccentricity of ellipse, e = c/a
Where c is the focal length and a is length of the semi-major axis.
Since c ≤ a the eccentricity is always greater than 1 in the case of an ellipse.
The correct answer is: 7x2 + 2xy + 7y2 – 10x + 10y + 7 = 0
We know that
The eccentricity of ellipse, e = c/a, where c is the focal length and a is length of the semi-major axis.
Thus, the equation of the ellipse whose focus is (1, -1). directrix x – y – 3 = 0 and eccentricity is
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