Maths-
General
Easy

Question

The number of real solutions of the equation s i n invisible function application open parentheses fraction numerator pi x over denominator 2 square root of 3 end fraction close parentheses equals x to the power of 2 end exponent minus 2 square root of 3 x plus 4is

  1. zero    
  2. one    
  3. two    
  4. more than two    

The correct answer is: one


    s i n invisible function application fraction numerator pi x over denominator 2 square root of 3 end fraction equals 1 equals x equals square root of 3
    no of real solutions = 1

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