Physics-
General
Easy

Question

A 100 m long rod of density 10.0 cross times 10 to the power of 4 end exponent k g divided by m to the power of 3 end exponent and having Young’s modules Y equals 10 to the power of 11 end exponent P a, is clamped at one end. It is hammered at the other free end. The longitudinal pulse goes to right end, gets reflected and again returns to the left end. How much time, the pulse take to go back to initial point

  1. 0.1 sec    
  2. 0.2 sec    
  3. 0.3 sec    
  4. 2 sec    

The correct answer is: 0.2 sec

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