Physics-
General
Easy

Question

A ball moving with a velocity v strikes a wall moving towards the ball with a velocity u as shown in fig. An elastic impact occurs. Consider the mass of the wall to be infinitely great. The work done by the wall during collision is

  1. 2 m u left parenthesis v plus u right parenthesis    
  2. m v to the power of 2 end exponent    
  3. fraction numerator 1 over denominator 2 end fraction m v to the power of 2 end exponent plus fraction numerator 1 over denominator 2 end fraction m u to the power of 2 end exponent    
  4. m left parenthesis v plus u right parenthesis to the power of 2 end exponent    

The correct answer is: 2 m u left parenthesis v plus u right parenthesis


    Initial K.E equals fraction numerator 1 over denominator 2 end fraction m v to the power of 2 end exponent; Final K.E = equals fraction numerator 1 over denominator 2 end fraction m left parenthesis v plus 2 u right parenthesis to the power of 2 end exponent
    fraction numerator 1 over denominator 2 end fraction m v to the power of 2 end exponent plus capital delta W equals fraction numerator 1 over denominator 2 end fraction m left parenthesis v plus 2 u right parenthesis to the power of 2 end exponent
    capital delta W equals fraction numerator m over denominator 2 end fraction.4 u to the power of 2 end exponent plus 2 m v u equals 2 m u left parenthesis u plus v right parenthesis

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