Physics-
General
Easy

Question

A particle of mass 0.1 kg is subjected to a force which varies with distance as shown in fig. If it starts its journey from rest at x equals 0, its velocity at x equals 12 m is

  1. 0 m/s    
  2. 20 square root of 2 m divided by s    
  3. 20 square root of 3 m divided by s    
  4. 40 m divided by s    

The correct answer is: 40 m divided by s


    Area between curve and displacement axis
    = fraction numerator 1 over denominator 2 end fraction cross times left parenthesis 12 plus 4 right parenthesis cross times 10= 80 J
    In this time body acquire kinetic energy = fraction numerator 1 over denominator 2 end fraction m v to the power of 2 end exponent
    by the law of conservation of energy
    fraction numerator 1 over denominator 2 end fraction m v to the power of 2 end exponent equals 80 J
    Þ fraction numerator 1 over denominator 2 end fraction cross times 0.1 cross times v to the power of 2 end exponent equals 80
    Þ v2 = 1600
    Þ v = 40 m/s

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