A bar magnet moves towards two identical parallel circular loops with a constant velocity v as shown in fig.

The correct answer is: The induced current in A is more than that in B

When a magnet is moved through the loops A and B with v velocity, the induced current in A is more than that of B.

• When the magnet moves towards two identical loops in v velocity, it creates electromagnetic induction in both loops.
• As a result, both A and B loops produce a flow of current.
• The current flow in the loop A will be more than that of loop B, as the loop A creates stronger magnetic field.
• The direction of the current produced in both A and B will be the same. So they'll be drawn to one another.
• Since A is nearer the magnet, its flux change rate will be greater. As a result, current in A is increased.