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Physics-

General

Easy

Question

A battery of e.m.f. 10 V is connected to resistance as shown in figure. The potential difference $V subscript A end subscript minus V subscript B end subscript$ between the points A and B is

$- 2 V$
$2 V$
$5 V$
$\frac{20}{11} V$

The correct answer is: $2 V$

$R subscript e q end subscript equals 5 capital omega$ , Current $i equals fraction numerator 10 over denominator 5 end fraction equals 2 A$ and current in each branch = 1A

Potential difference between C and A,
$V subscript C end subscript minus V subscript A end subscript equals 1 cross times 1 equals 1 V$ .......(i)
Potential difference between C and B,
$V subscript C end subscript minus V subscript B end subscript equals 1 cross times 3 equals 3 V$ ......(ii)
On solving (i) and (ii) $V subscript A end subscript minus V subscript B end subscript equals 2 v o l t$
Shot Trick : $left parenthesis V subscript A end subscript minus V subscript B end subscript right parenthesis equals fraction numerator i over denominator 2 end fraction left parenthesis R subscript 2 end subscript minus R subscript 1 end subscript right parenthesis equals fraction numerator 2 over denominator 2 end fraction left parenthesis 3 minus 1 right parenthesis equals 2 V$

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