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Question

A body falling from a high Minaret travels 40 blank m in the last 2 seconds of its fall to ground. Height of Minaret in meters is (take g equals 10 blank m divided by s to the power of negative 2 end exponent)

  1. 60  
  2. 45  
  3. 80  
  4. 50  

The correct answer is: 45


    Let height of minaret is H and body take time T to fall from top to bottom

    H equals fraction numerator 1 over denominator 2 end fraction g T to the power of 2 end exponent(i)
    In last 2 blank s e c body travels distance of 40 blank m so in open parentheses T minus 2 close parentheses blank s e c distance travelled equals left parenthesis H minus 40 right parenthesis m
    open parentheses H minus 40 close parentheses equals fraction numerator 1 over denominator 2 end fraction g open parentheses T minus 2 close parentheses to the power of 2 end exponent(ii)
    By solving (i) and (ii), T equals 3 blank s e c and H equals 45 m

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