Physics-
General
Easy

Question

A body is projected with initial velocity of left parenthesis 8 stack i with hat on top plus 6 stack j with hat on top right parenthesis m s to the power of negative 1 end exponent. The horizontal range is

  1. 9.6 m  
  2. 14 m  
  3. 50 m  
  4. None of these  

The correct answer is: 9.6 m


    Here,
    v equals square root of open parentheses 8 close parentheses to the power of 2 end exponent plus open parentheses 6 close parentheses to the power of 2 end exponent end root equals 10 and tan invisible function application theta equals fraction numerator 6 over denominator 8 end fraction
    therefore blankHypotenuse, h equals 10m
    therefore blank s i n blank theta equals fraction numerator 6 over denominator 10 end fraction comma cos invisible function application theta equals fraction numerator 8 over denominator 10 end fraction
    R equals fraction numerator 2 u to the power of 2 end exponent sin invisible function application theta cos invisible function application theta over denominator g end fraction
    R equals fraction numerator 2 cross times 10 cross times 10 cross times fraction numerator 6 over denominator 10 end fraction cross times fraction numerator 8 over denominator 10 end fraction over denominator 10 end fraction
    R equals fraction numerator 96 over denominator 10 end fraction equals 9.6 m

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