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Question

A bus begins to move with an acceleration of 1 m s to the power of negative 2 end exponent. A man who is 48 m behind the bus starts running at 10 blank m s to the power of negative 1 end exponent to catch the bus. The man will be able to catch the bus after

  1. 6 s  
  2. 5 s  
  3. 3 s  
  4. 8 s  

The correct answer is: 8 s


    Let the man will be able to catch the bus after t blank s
    Then
    10 t equals 48 plus fraction numerator 1 over denominator 2 end fraction cross times 1 cross times t to the power of 2 end exponent
    t to the power of 2 end exponent minus 20 t plus 96 equals 0
    open parentheses t minus 12 close parentheses open parentheses t minus 8 close parentheses equals 0
    t equals 8 s and t equals 12 s
    Thus the man will be able to catch the bus after 8 s

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