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Physics-

General

Easy

Question

A car is circulating on the path of radius $r$ and at any time its velocity is $v$ and rate of increases of velocity is $a$ . The resultant acceleration of the car will be

$\sqrt{\frac{v^{2}}{a^{2}} + r^{2}}$
$\sqrt{\frac{v^{2}}{r} + a}$
$\sqrt{\frac{v^{4}}{r^{2}} + a^{2}}$
$(\frac{v^{2}}{r} + a)$

The correct answer is: $square root of fraction numerator v to the power of 4 end exponent over denominator r to the power of 2 end exponent end fraction plus a to the power of 2 end exponent end root$

Resultant acceleration
$equals square root of open parentheses table row cell t a n g e n t i a l end cell row cell a c c e l e r a t i o n end cell end table close parentheses to the power of 2 end exponent plus open parentheses table row cell c e n t r i p e t a l end cell row cell a c c e l e r a t i o n end cell end table close parentheses to the power of 2 end exponent end root$
$equals square root of a to the power of 2 end exponent plus open parentheses fraction numerator v to the power of 2 end exponent over denominator r end fraction close parentheses to the power of 2 end exponent end root equals square root of fraction numerator v to the power of 4 end exponent over denominator r to the power of 2 end exponent end fraction plus a to the power of 2 end exponent end root$

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