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Question

A car runs at a constant speed on a circular track of radius 100blank m comma taking 62.8 s e c o n d s for every circular loop. The average velocity and average speed for each circular loop respectively is

  1. 10m divided by s comma 10 m divided by s  
  2. 10blank m divided by s,0  
  3. 0 comma blank 0  
  4. 010 blank m divided by s  

The correct answer is: 010 blank m divided by s


    Net displacement in one loop = 0
    Average velocity equals fraction numerator n e t blank d i s p l a c e m e n t over denominator t i m e end fraction equals fraction numerator 0 over denominator t end fraction equals 0
    Distance travelled in one rotation (loop) = 2 pi r
    therefore A v e r a g e blank s p e e d equals fraction numerator d i s t a n c e over denominator t i m e end fraction equals fraction numerator 2 pi r over denominator t end fraction
    equals fraction numerator 2 cross times 3.14 cross times 100 over denominator 62.8 end fraction equals 10 m divided by s.

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