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Question

A coil of wire of a certain radius has 600 turns and a self inductanceof 108 blank m H. The self inductance of a 2nd similar coil of 500 turns will be

  1. 74 blank m H  
  2. 75 blank m H  
  3. 76 blank m H  
  4. 77 blank m H  

The correct answer is: 75 blank m H


    fraction numerator L subscript B end subscript over denominator L subscript A end subscript end fraction equals open parentheses fraction numerator n subscript B end subscript over denominator n subscript A end subscript end fraction close parentheses to the power of 2 end exponent rightwards double arrow L subscript B end subscript equals open parentheses fraction numerator 500 over denominator 600 end fraction close parentheses to the power of 2 end exponent rightwards double arrow 108 equals 75 blank m H

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