Physics-
General
Easy
Question
A conductor ABOCD moves along its bisector with a velocity of 1 m/s through a perpendicular magnetic field of 1 wb/m2, as shown in fig. If all the four sides are of 1m length each, then the induced emf between points A and D is
- 0
- 1.41 volt
- 0.71 volt
- None of the above
The correct answer is: 1.41 volt
There is no induced emf in the part AB and CD because they are moving along their length while emf induced between B and C i.e. between A and D can be calculated as follows
Induced emf between B and C = Induced emf between A and B = 
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