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Physics

Fluid-Mechanics

Easy

Question

A fire engine pumps water from a tank at $1000 text lits end text to the power of negative 1 end exponent$ . It ejects the water from a nozzle 5 m above the surface of water in the tank with a velocity of $10 m s to the power of negative 1 end exponent$ . The pressure difference between the water at the pump and the nozzle is $open parentheses g equals 10 m s to the power of negative 2 end exponent close parentheses$ .

$10^{3} P a$
$10^{4} P a$
$10^{5} P a$
$10^{6} P a$

The correct answer is: $10 to the power of 5 P a$

$table attributes columnalign left end attributes row cell P subscript 1 plus 1 half rho v subscript 1 superscript 2 plus rho g h subscript 1 equals P subscript 2 plus 1 half rho v subscript 2 superscript 2 plus rho g h subscript 2 end cell row cell P subscript 1 minus P subscript 2 equals 1 half rho open parentheses v subscript 2 superscript 2 minus v subscript 1 superscript 2 close parentheses plus rho g open parentheses h subscript 2 minus h subscript 1 close parentheses end cell row cell P subscript 1 minus P subscript 2 equals 1 half cross times 10 cubed cross times 10 squared plus 10 cubed cross times 10 cross times 5 equals 10 to the power of 5 P a end cell end table$

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