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Physics-

General

Easy

Question

A juggler throws balls into air. He throws one whenever the previous one is at its highest point. If the throws $n$ balls each second, the height to which each ball will rise is

$\frac{g}{2 n^{2}}$
$\frac{2 g}{n^{2}}$
$\frac{2 g}{n^{}}$
$\frac{g}{4 n^{2}}$

The correct answer is: $fraction numerator g over denominator 2 n to the power of 2 end exponent end fraction$

Time taken by each ball to reach highest point,
$t equals fraction numerator 1 over denominator n end fraction$ s.
As the juggler throws the second ball, when the first ball is at its highest point, so $v equals 0$
Using $v equals u plus a t comma$ we have $0 equals u plus open parentheses negative g close parentheses left parenthesis 1 divided by n right parenthesis$
or $u equals left parenthesis g divided by n right parenthesis$
Also $v to the power of 2 end exponent equals u to the power of 2 end exponent plus 2 a s$
$therefore 0 equals open parentheses g divided by n close parentheses to the power of 2 end exponent plus 2 open parentheses negative g close parentheses h$ or $h equals fraction numerator g over denominator 2 n to the power of 2 end exponent end fraction.$

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