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A liquid of density 800 kg m-3 is filled in a tank open at the top. The pressure, of the liquid, at the bottom of the tank is 6.4 atmospheres. The velocity of efflux through a hole at the bottom is text  (1 atmosphere  end text equals 10 to the power of 5 Nm to the power of negative 2 end exponent text ).  end text

  1. 10 ms to the power of negative 1 end exponent
  2. 20 ms to the power of negative 1 end exponent
  3. 30 m s to the power of negative 1 end exponent
  4. 40 m s to the power of negative 1 end exponent

The correct answer is: 40 m s to the power of negative 1 end exponent


    table attributes columnalign left columnspacing 1em rowspacing 4 pt end attributes row cell v equals square root of 2 g h end root end cell row cell text  But  end text h rho g equals p therefore h g equals p over rho end cell row cell therefore space of 1em v equals square root of fraction numerator 2 p over denominator rho end fraction end root equals square root of fraction numerator 2.6.4 cross times 10 to the power of 5 over denominator 800 end fraction end root ms to the power of negative 1 end exponent equals 40 ms to the power of negative 1 end exponent end cell end table

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