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Question

A man walks on a straight road from his home to a market 2.5 blank k m away with a speed of 5 blank k m divided by h. Finding the market closed, he instantly turns and walks back home with a speed of 7.5 blank k m divided by h. The average speed of the man over the interval of time 0 to 40 blank m i n. Is equal to

  1. 5 blank k m divided by h  
  2. fraction numerator 25 over denominator 4 end fraction blank k m divided by h  
  3. fraction numerator 30 over denominator 4 end fraction blank k m divided by h  
  4. fraction numerator 45 over denominator 8 end fraction blank k m divided by h  

The correct answer is: fraction numerator 45 over denominator 8 end fraction blank k m divided by h


    Man walks from his home to market with a speed of 5 blank k m divided by h. Distanceequals 2.5 blank k m and time equals fraction numerator d over denominator v end fraction equals fraction numerator 2.5 over denominator 5 end fraction equals fraction numerator 1 over denominator 2 end fraction blank h r and he returns back with speed of 7.5 blank k m divided by h in rest of time of 10 blank m i n u t e s
    Distance equals 7.5 cross times fraction numerator 10 over denominator 60 end fraction equals 1.25 blank k m
    So, Average speed equals fraction numerator T o t a l blank d i s t a n c e over denominator T O t a l blank t i m e end fraction
    equals fraction numerator left parenthesis 2.5 plus 1.25 right parenthesis k m over denominator left parenthesis 40 divided by 60 right parenthesis h r end fraction equals fraction numerator 45 over denominator 8 end fraction k m divided by h r

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