Physics-
General
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Question

A particle is projected upwards. The times corresponding to height h while ascending and while descending are t subscript 1 end subscript and t subscript 2 end subscript respectively. The velocity of projection will be

  1. g t subscript 1 end subscript  
  2. g t subscript 2 end subscript  
  3. g left parenthesis t subscript 1 end subscript plus t subscript 2 end subscript right parenthesis  
  4. fraction numerator g left parenthesis t subscript 1 end subscript plus t subscript 2 end subscript right parenthesis over denominator 2 end fraction  

The correct answer is: fraction numerator g left parenthesis t subscript 1 end subscript plus t subscript 2 end subscript right parenthesis over denominator 2 end fraction


    If t subscript 1 end subscript and t subscript 2 end subscript are time of ascent and descent respectively then time of flight T equals t subscript 1 end subscript plus t subscript 2 end subscript equals fraction numerator 2 u over denominator g end fraction
    rightwards double arrow u equals fraction numerator g left parenthesis t subscript 1 end subscript plus t subscript 2 end subscript right parenthesis over denominator 2 end fraction

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