Physics-
General
Easy

Question

A particle moves along a straight line such that its displacement at any time t is given by S equals t to the power of 3 end exponent minus 6 t to the power of 2 end exponent plus 3 t plus 4 blank m e t r e s
The velocity when the acceleration is zero is

  1. 3 m s to the power of negative 1 end exponent  
  2. negative 12 m s to the power of negative 1 end exponent  
  3. 42 m s to the power of negative 1 end exponent  
  4. negative 9 m s to the power of negative 1 end exponent  

The correct answer is: negative 9 m s to the power of negative 1 end exponent


    v equals fraction numerator d s over denominator d t end fraction equals 3 t to the power of 2 end exponent minus 12 t plus 3 and a equals fraction numerator d v over denominator d t end fraction equals 6 t minus 12
    For a equals 0, we have t equals 2 and at t equals 2 comma blank v equals negative 9 blank m s to the power of negative 1 end exponent

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