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Physics-

General

Easy

Question

A particle moves along a straight line such that its displacement at any time $t$ is given by $S equals t to the power of 3 end exponent minus 6 t to the power of 2 end exponent plus 3 t plus 4 blank m e t r e s$
The velocity when the acceleration is zero is

$3 m s^{- 1}$
$- 12 m s^{- 1}$
$42 m s^{- 1}$
$- 9 m s^{- 1}$

The correct answer is: $negative 9 m s to the power of negative 1 end exponent$

$v equals fraction numerator d s over denominator d t end fraction equals 3 t to the power of 2 end exponent minus 12 t plus 3$ and $a equals fraction numerator d v over denominator d t end fraction equals 6 t minus 12$
For $a equals 0$ , we have $t equals 2$ and at $t equals 2 comma blank v equals negative 9 blank m s to the power of negative 1 end exponent$

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