Physics-
General
Easy

Question

With what velocity a ball be projected vertically so that the distance covered by it in 5th second is twice the distance it covers in its 6th second (g equals 10 blank m divided by s to the power of 2 end exponent)

  1. 58.8 blank m divided by s  
  2. 49 blank m divided by s  
  3. 65 blank m divided by s  
  4. 19.6 blank m divided by s  

The correct answer is: 65 blank m divided by s


    h subscript n to the power of t h end exponent end subscript equals u minus fraction numerator g over denominator 2 end fraction left parenthesis 2 n minus 1 right parenthesis
    h subscript 5 to the power of t h end exponent end subscript equals u minus fraction numerator 10 over denominator 2 end fraction open parentheses 2 cross times 5 minus 1 close parentheses equals u minus 45
    h subscript 6 to the power of t h end exponent end subscript equals u minus fraction numerator 10 over denominator 2 end fraction open parentheses 2 cross times 6 minus 1 close parentheses equals u minus 55
    Given h subscript 5 to the power of t h end exponent end subscript equals 2 cross times h subscript 6 to the power of t h end exponent end subscript.By solving we get u equals 65 blank m divided by s

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