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Question

A particle moves for 20 s with velocity blank 3 blank m s to the power of negative 1 end exponent and then moves with velocity 4 blank m s to the power of negative 1 end exponent for another 20 s and finally moves with velocity 5 blank m s to the power of negative 1 end exponent for next 20 s. What is the average velocity of the particle?

  1. 3 blank m s to the power of negative 1 end exponent  
  2. 4 blank m s to the power of negative 1 end exponent  
  3. 5 blank m s to the power of negative 1 end exponent  
  4. Zero  

The correct answer is: 4 blank m s to the power of negative 1 end exponent


    Average velocity is that uniform velocity with which the object will cover the same displacement in same interval of time as it does with its actual variable velocity during that time interval.
    Here, total distance covered
    blank equals open parentheses 3 blank m s to the power of negative 1 end exponent cross times 20 blank s close parentheses plus open parentheses 4 blank m s to the power of negative 1 end exponent cross times 20 blank s close parentheses plus open parentheses 5 blank m s to the power of negative 1 end exponent cross times 20 blank s close parentheses
    blank equals open parentheses 60 plus 80 plus 100 close parentheses equals 240 blank m
    T o t a l blank t i m e blank t a k e n equals 20 plus 20 plus 20 equals 60 blank s
    therefore A v e r a g e blank v e l o c i t y equals fraction numerator 240 over denominator 60 end fraction equals 4 blank m s to the power of negative 1 end exponent

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