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Physics-

General

Easy

Question

A particle moving in a straight line with uniform acceleration is observed to be a distance $a$ from a fixed point initially. It is at distances $b comma c comma d blank$ from the same point after $n comma 2 n comma 3 n$ second. The acceleration of the particle is

$\frac{c - 2 b + a}{n^{2}}$
$\frac{c + b + a}{{9 n}^{2}}$
$\frac{c + 2 b + a}{{4 n}^{2}}$
$\frac{c - b + a}{n^{2}}$

The correct answer is: $fraction numerator c minus 2 b plus a over denominator n to the power of 2 end exponent end fraction$

$b minus a equals u n plus fraction numerator 1 over denominator 2 end fraction A n to the power of 2 end exponent$
$2 b minus 2 a equals 2 u n plus A n to the power of 2 end exponent$

Again, $c minus a equals u open parentheses 2 n close parentheses plus fraction numerator 1 over denominator 2 end fraction A open parentheses 2 n close parentheses to the power of 2 end exponent$
Subtracting, $c minus a minus 2 b plus 2 a equals A n to the power of 2 end exponent$
$A equals fraction numerator c minus 2 b plus a over denominator n to the power of 2 end exponent end fraction$

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