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Physics-

General

Easy

Question

A particle of mass $m$ moves with constant speed along a circular path of radius $r$ under the action of force $F$ . Its speed is

$\sqrt{F r / m}$
$\sqrt{F / r}$
$\sqrt{F m r}$
$\sqrt{F / m r}$

The correct answer is: $square root of F r divided by m end root$

$F equals fraction numerator m v to the power of 2 end exponent over denominator r end fraction$ or $v equals square root of fraction numerator F r over denominator m end fraction end root$

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