Physics-
General
Easy

Question

A particle starts from rest, acceleration at 2 blank m divided by s to the power of 2 end exponent for 10 blank s and then goes with constant speed for 30 blank s and then decelerates at 4 blank m divided by s to the power of 2 end exponent till it stops. What is the distance travelled by it

  1. 750 blank m  
  2. 800 blank m  
  3. 700 blank m  
  4. 850 blank m  

The correct answer is: 750 blank m


    Velocity required by body in 10 blank s e c
    v equals 0 plus 2 cross times 10 equals 20 blank m divided by s
    And distance travelled by it in 10 blank s e c
    S subscript 1 end subscript equals fraction numerator 1 over denominator 2 end fraction cross times 2 cross times open parentheses 10 close parentheses to the power of 2 end exponent equals 100 blank m
    Then it moves with constant velocity left parenthesis 20 blank m divided by s right parenthesis for 30 blank s e c
    S subscript 2 end subscript equals 20 cross times 30 equals 600 blank m
    After that due to retardation left parenthesis 4 blank m divided by s to the power of 2 end exponent right parenthesis it stops
    S subscript 3 end subscript equals fraction numerator v to the power of 2 end exponent over denominator 2 a end fraction equals fraction numerator open parentheses 20 close parentheses to the power of 2 end exponent over denominator 2 cross times 4 end fraction equals 50 m
    Total distance travelled S subscript 1 end subscript plus S subscript 2 end subscript plus S subscript 3 end subscript equals 750 m

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