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Physics

Fluid-Mechanics

Easy

Question

A steel bolt of cross-sectional area $A subscript b equals 5 cross times 10 to the power of negative 5 end exponent straight m squared$ is passed through a cylindrical tube made of aluminium. Cross-sectional area of the tube material is $A subscript t equals 10 to the power of negative 4 end exponent m squared$ and its length is l =50 cm. The bolt is just taut to that there is no stress in the bolt and temperature of the assembly increases through $straight capital delta theta equals 10 to the power of ring operator straight C$ . Given, coefficient of linear thermal expansion of steel, $alpha subscript b equals 10 to the power of negative 5 end exponent divided by to the power of ring operator straight C$
.
Young 's modulus of steel $Y subscript b equals 2 cross times 10 to the power of ′′ N divided by m squared$
Young's modulus of $A l comma Y subscript t equals 10 to the power of 11 N divided by m squared$ ,coefficient of
linear thermal expansion of $A l alpha subscript t equals 2 cross times 10 to the power of negative 5 end exponent divided by to the power of ring operator straight C$
The compressive stress in tube is

$5 \times 10^{6} N / m^{2}$
$10^{5} N / m^{2}$
$10^{8} N / m^{2}$
$10^{3} N / m^{2}$

The correct answer is: $5 cross times 10 to the power of 6 N divided by m squared$

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