Physics
Fluid-Mechanics
Easy

Question

A wire of cross-section area 3.0 mm2 and natural length 50 cm is fixed at one end and a mass of 2.1 kg is hung from the other end. Young’s modulus of the material of wire is 1.9 cross times 10 to the power of 11 N divided by m squared. The potential energy stored in the wire in steady state will be (g = 10 m/s2)

  1. 1.9 cross times 10 to the power of negative 5 end exponent J
  2. 1.9 cross times 10 to the power of negative 4 end exponent J
  3. 1.9 cross times 10 to the power of negative 5 end exponent J
  4. 9.1 cross times 10 to the power of negative 5 end exponent J

The correct answer is: 1.9 cross times 10 to the power of negative 4 end exponent J


    U equals 1 half F capital delta L    equals 1 half F open parentheses fraction numerator F L over denominator A Y end fraction close parentheses equals 1.9 cross times 10 to the power of negative 4 end exponent J

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