Physics-
General
Easy

Question

An electron (mass = 9× 10–31kg. Charge = 1.6 × 10–19C) whose kinetic energy is 7.2 × 10–18 joule is moving in a circular orbit in a magnetic field of 9 × 10–5 weber/m2. The radius of the orbit is

  1. 1.25 cm    
  2. 2.5 cm    
  3. 12.5 cm    
  4. 25.0 cm    

The correct answer is: 25.0 cm


    r equals fraction numerator square root of 2 m E end root over denominator q B end fraction equals fraction numerator square root of 2 cross times 9 cross times 1 0 to the power of negative 31 end exponent cross times 7.2 cross times 1 0 to the power of negative 18 end exponent end root over denominator 1.6 cross times 1 0 to the power of negative 19 end exponent cross times 9 cross times 1 0 to the power of negative 5 end exponent end fraction
    = 0.25 m = 25 cm

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