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General
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Question

An energy of 24.6 eV is required to remove one of the electrons from a neutral helium atom. The energy (in eV) required to remove both the electrons from a neutral helium atom is

  1. 79.0    
  2. 51.8    
  3. 49.2    
  4. 38.2    

The correct answer is: 79.0


    After the removal of first electron remaining atom will be hydrogen like atom.
    So energy required to remove second electron from the atom E equals 13.6 cross times fraction numerator 2 to the power of 2 end exponent over denominator 1 end fraction equals 54.4 e V
    \ Total energy required = 24.6 + 54.4 = 79 eV

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