Physics-
General
Easy

Question

An inductance L and a resistance R are first connected to a battery. After some time the battery is disconnected but L and R remain connected in a closed circuit. Then the current reduces to 37% of its initial value in

  1. R L blank s e c  
  2. R divided by L blank s e c  
  3. L divided by R blank s e c  
  4. 1 divided by L R blank s e c  

The correct answer is: L divided by R blank s e c


    When battery is disconnected current through the circuit starts decreasing exponentially according to i equals i subscript 0 end subscript e to the power of negative R t divided by L end exponent
    rightwards double arrow 0.37 i subscript 0 end subscript equals i subscript 0 end subscript e to the power of negative R t divided by L end exponent rightwards double arrow 0.37 equals fraction numerator 1 over denominator e end fraction equals e to the power of negative R t divided by L end exponent rightwards double arrow t equals fraction numerator L over denominator R end fraction

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