Physics
Grade-10
Easy

Question

An object of mass 50 Kg acquires the final velocity of 7 m/s from 5 m/s after 2 seconds. What is the net force applied?

  1. 300 N
  2. 50 N
  3. 200 N
  4. 100 N

hintHint:

Force =m a s s space cross times a c c e l e r a t i o n

The correct answer is: 50 N


    Force =m a s s space cross times a c c e l e r a t i o n
    acceleration = fraction numerator c h a n g e space i n space v e l o c i t y space space over denominator t i m e end fraction=fraction numerator left parenthesis 7 minus 5 right parenthesis m divided by s over denominator 2 end fraction equals 1
    Force =50cross times1=50 N

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