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$Angular space momentum space of space the space particle space rotating space with space straight a space central space force space is space constant space due space to space minus space space$

$constant torque$
$constant force$
$constant linear momentum$
$zero torque$

The correct answer is: $space zero space torque space space$

$space Sol. colon space Torque space of space central space force space straight w. straight r. straight t. space CM space is space zero space space space Angular space momentum space is space constant space space space space space space space space$
Ans : (4)
Sol.: Q Torque of central force w.r.t. CM is zero
\ Angular momentum is constant

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$Angular space momentum space of space the space particle space rotating space with space straight a space central space force space is space constant space due space to space minus space space$

$constant torque$
$constant force$
$constant linear momentum$
$zero torque$

The correct answer is: $space zero space torque space space$

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$When space straight a space mass space is space rotated space in space straight a space plane space about space is space fixed space point comma space its space angular space momentum space is space directed space along space the minus$

The minimum height of the obstacle so that the sphere can stay in equilibrium is (R is radius of the sphere)

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An isosceles right triangular plate ABC of mass m is free to rotate in vertical plane about a fixed horizontal axis through A. It is supported by a string such that the side AB is horizontal. The reaction at the support A is

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In the above case rod does not slip until $theta equals$

In the above case rod does not slip until $theta equals$

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$text In the above situation of end text mu text is coefficient of friction between the rod and the surface end text tan invisible function application theta equals$

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The correct answer is:

Ans : (4)Sol.: Q Torque of central force w.r.t. CM is zero \ Angular momentum is constant

Related Questions to study

The minimum height of the obstacle so that the sphere can stay in equilibrium is (R is radius of the sphere)

The minimum height of the obstacle so that the sphere can stay in equilibrium is (R is radius of the sphere)

The maximum ratio of b/h for which the homogeneous block will slide without toppling under the action of force F. Coefficient of static friction between the block and incline is .

The maximum ratio of b/h for which the homogeneous block will slide without toppling under the action of force F. Coefficient of static friction between the block and incline is .

A horizontal force F is applied at the top of an equilateral triangular block of mass m and side L as shown. The minimum value of coefficient of friction between block and the horizontal surface to topple the block before it slides.

A horizontal force F is applied at the top of an equilateral triangular block of mass m and side L as shown. The minimum value of coefficient of friction between block and the horizontal surface to topple the block before it slides.

A cubical block of mass m and edge length L is sliding down on an inclined plane with uniform velocity. Torque due to the normal force applied by the incline on the block about its centre of mass is

A cubical block of mass m and edge length L is sliding down on an inclined plane with uniform velocity. Torque due to the normal force applied by the incline on the block about its centre of mass is

An isosceles right triangular plate ABC of mass m is free to rotate in vertical plane about a fixed horizontal axis through A. It is supported by a string such that the side AB is horizontal. The reaction at the support A is

An isosceles right triangular plate ABC of mass m is free to rotate in vertical plane about a fixed horizontal axis through A. It is supported by a string such that the side AB is horizontal. The reaction at the support A is

In the above case rod does not slip until

In the above case rod does not slip until

A rod of mass m and length L is released from rest from vertical position as shown. The normal force exerted on the rod by ground as function of as rod falls downward without slip

A rod of mass m and length L is released from rest from vertical position as shown. The normal force exerted on the rod by ground as function of as rod falls downward without slip

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The correct answer is: $space zero space torque space space$

The maximum ratio of b/h for which the homogeneous block will slide without toppling under the action of force F. Coefficient of static friction between the block and incline is $mu$ .

The maximum ratio of b/h for which the homogeneous block will slide without toppling under the action of force F. Coefficient of static friction between the block and incline is $mu$ .

In the above case rod does not slip until $theta equals$

In the above case rod does not slip until $theta equals$