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Question

Consider the arrangement shown in figure. By some mechanism, the separation between the slits S subscript 3 end subscript and S subscript 4 end subscript can be changed. The intensity is measured at the point P which is at the common perpendicular bisector of S subscript 1 end subscript S subscript 2 end subscript and S subscript 3 end subscript S subscript 4 end subscript. When z equals fraction numerator D lambda over denominator 2 blank d end fraction, the intensity measured at P is I. Find this intensity when z is equal to

1) fraction numerator D lambda over denominator d end fraction,
2) fraction numerator 3 D lambda over denominator 2 blank d end fraction, and
3) fraction numerator 2 D lambda over denominator d end fraction.

  1. O,I,2I    
  2. I,O,2I    
  3. 2I,O,I    
  4. I,2I,3I    

The correct answer is: O,I,2I

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