Physics
Grade-10
Easy
Question
For an object standing in front of a spherical mirror, the object distance is _____.
Hint:
Negative
The correct answer is: Negative
object placed in front of the mirror has a negative object distance.
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The height of a virtual and upright image is ____ as per the new cartesian sign convention.
The height of a virtual and upright image is ____ as per the new cartesian sign convention.
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The height of a real and inverted image is _____ as per the new cartesian sign convention.
The height of a real and inverted image is _____ as per the new cartesian sign convention.
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Before plugging in the values of various quantities in the expression to calculate the magnification it is important to _____.
Before plugging in the values of various quantities in the expression to calculate the magnification it is important to _____.
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The magnification of the image of an object is found to be 1.25. Which of the following is true about it?
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An object is placed at a distance of 20 cm from a convex mirror. Its image is formed at a distance of 10 cm from the mirror. The magnification is ____.
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Which of the following should be taken as negative according to the new cartesian sign convention? (Note: the object is standing in front of a concave mirror.)
all the given cases show negative signs for a concave mirror.
Which of the following should be taken as negative according to the new cartesian sign convention? (Note: the object is standing in front of a concave mirror.)
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all the given cases show negative signs for a concave mirror.
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The height of a real and inverted image of an object of size 4 cm is 20 cm. The ratio of the image distance and the object distance is _____.
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Which of the following should be taken as positive according to the new cartesian sign convention? (Note: the object is standing in front of the mirror along the +y direction.)
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both the height of an object and the height of a virtual and upright image are positive.
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A real image is always _____.
the real image is always formed as inverted, therefore, for real image height is taken as negative.
A real image is always _____.
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the real image is always formed as inverted, therefore, for real image height is taken as negative.
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An object of size 12 cm is placed in front of a concave mirror, it forms a real and inverted image of size 18 cm. What is the magnification of the image?
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The position of an object is always taken to be towards the ____ of the mirror.
object is always placed to the left of mirror.
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object is always placed to the left of mirror.
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The magnification of an image is found to be -2.5. Which of the following is true about it?
a. It is real and inverted
b. It is diminished
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The magnification of an image is found to be -2.5. Which of the following is true about it?
a. It is real and inverted
b. It is diminished
c. It is magnified
d. It is formed in front of the concave mirror
e. It is formed behind the mirror
f. It is virtual and upright
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In the following figure, the magnification of the candle's image is____.
In the following figure, the magnification of the candle's image is____.
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In which of the following cases is the image produced not magnified?
In which of the following cases is the image produced not magnified?
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The focal length of any spherical mirror is ____ its radius of curvature.
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