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Question

If a train travelling at 72 blank k m p h is to be brought to rest in a distance of 200 blankmetres, then its retardation should be

  1. 20 blank m s to the power of negative 2 end exponent  
  2. 10 blank m s to the power of negative 2 end exponent  
  3. 2 blank m s to the power of negative 2 end exponent  
  4. 1 m s to the power of negative 2 end exponent  

The correct answer is: 1 m s to the power of negative 2 end exponent


    u equals 72 blank k m p h equals 20 blank m divided by s comma blank v equals 0
    By using v to the power of 2 end exponent equals u to the power of 2 end exponent minus 2 a s rightwards double arrow a equals fraction numerator u to the power of 2 end exponent over denominator 2 s end fraction equals fraction numerator open parentheses 20 close parentheses to the power of 2 end exponent over denominator 2 cross times 200 end fraction equals 1 blank m divided by s to the power of 2 end exponent

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