Physics-
General
Easy

Question

If E is the electric field intensity of an electrostatic field, then the electrostatic energy density is proportional to

  1. E    
  2. E to the power of 2 end exponent    
  3. 1 divided by E to the power of 2 end exponent    
  4. E to the power of 3 end exponent    

The correct answer is: E to the power of 2 end exponent


    Electrostatic energy density fraction numerator d U over denominator d V end fraction equals fraction numerator 1 over denominator 2 end fraction K epsilon subscript 0 end subscript E to the power of 2 end exponent
    \ fraction numerator d U over denominator d V end fraction proportional to E to the power of 2 end exponent

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