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Physics

Mechanics

Easy

Question

If I is moment of inertia of a thin circular plate about an axis passing, through tangent of plate in its plane. The moment of inertia of same circular plate about an axis perpendicular to its plane and passing through its center is

$\frac{4 I}{5}$
$\frac{2 I}{5}$
$\frac{4 I}{3}$
$\frac{2 I}{3}$

The correct answer is: $fraction numerator 2 I over denominator 5 end fraction$

$I equals fraction numerator 5 M R squared over denominator 4 end fraction straight & space I to the power of apostrophe equals fraction numerator M R squared over denominator 2 end fraction$

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