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Physics-

General

Easy

Question

In a coil when current changes from 10A to 2A in time 0.1s, induced emf is 3.28 V. what is self –inductance of coil?

4 H
0.4 H
0.04 H
5 H

The correct answer is: 0.04 H

The induced emf is
$e equals negative L fraction numerator d i over denominator d t end fraction$
Here, $d i equals open parentheses 2 minus 10 close parentheses A equals negative 8 blank A comma blank d t equals 0.1 s comma blank e equals 3.28 blank V.$
$therefore blank 3.28 equals blank minus fraction numerator L open parentheses negative 8 close parentheses over denominator 0.1 end fraction$
$therefore blank L equals fraction numerator 3.28 cross times 0.1 over denominator 8 end fraction equals 0.04 H$

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