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Physics-

General

Easy

Question

In an adjoining figure are shown three capacitors $C subscript 1 end subscript$ , $C subscript 2 end subscript$ and $C subscript 3 end subscript$ joined to a battery. The correct condition will be (Symbols have their usual meanings)

$Q_{1} = Q_{2} = Q_{3}$ and $V_{1} = V_{2} = V_{3} = V$
$Q_{1} = Q_{2} + Q_{3}$ and $V = V_{1} + V_{2} + V_{3}$
$Q_{1} = Q_{2} + Q_{3}$ and $V = V_{1} + V_{2}$
$Q_{2} = Q_{3}$ and $V_{2} = V_{3}$

The correct answer is: $Q subscript 1 end subscript equals Q subscript 2 end subscript plus Q subscript 3 end subscript$ and $V equals V subscript 1 end subscript plus V subscript 2 end subscript$

$Q subscript 1 end subscript equals Q subscript 2 end subscript plus Q subscript 3 end subscript$ because in series combination charge is same on both the condenser and $V equals V subscript 1 end subscript plus V subscript 2 end subscript$ because in parallel combination $V subscript 2 end subscript equals V subscript 3 end subscript.$
Hence $V equals V subscript 1 end subscript plus V subscript 2 end subscript$

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