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Physics-

General

Easy

Question

In the figure, the distribution of energy density of the radiation emitted by a black body at a given temperature is shown. The possible temperature of the black body is

1500 K
2000 K
2500 K
3000 K

The correct answer is: 2000 K

$lambda subscript m end subscript T equals b$ where $b equals 2.89 cross times 1 0 to the power of negative 3 end exponent m K$
Þ $T equals fraction numerator b over denominator lambda subscript m end subscript end fraction equals fraction numerator 2.89 cross times 1 0 to the power of negative 3 end exponent over denominator 1.5 cross times 1 0 to the power of negative 6 end exponent end fraction almost equal to 2000 K$

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Radius of a conductor increases uniformly from left end to right end as shown in fig.

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