Physics-
General
Easy

Question

In the following arrangement y = 1.0 mm, d= 0.24 mm and D = 1.2 m. The work function of the material of the emitter is 2.2 eV. The stopping potential V needed to stop the photo current will be

  1. 0.9 V    
  2. 0.5 V    
  3. 0.4 V    
  4. 0.1 V    

The correct answer is: 0.9 V


    As we know in Young's double slit experiment fringe width = separation between two consecutive fringe or dark fringes equals beta equals fraction numerator lambda D over denominator d end fraction
    Here beta equals 2 y Þ 2 y equals fraction numerator lambda D over denominator d end fraction Þ lambda equals fraction numerator 2 y d over denominator D end fraction
    Þ lambda equals fraction numerator 2 cross times 1 cross times 1 0 to the power of negative 3 end exponent cross times 0.24 cross times 1 0 to the power of negative 3 end exponent over denominator 1.2 end fraction equals 4 cross times 1 0 to the power of negative 7 end exponent m equals 4000 Å
    Energy of light incident on photo plate
    E left parenthesis e V right parenthesis equals fraction numerator 12375 over denominator 4000 end fraction equals 3.1 e V
    According to Eienstein photoelectric equation
    E = W0 + eV0 Þ V subscript 0 end subscript equals fraction numerator left parenthesis E minus W subscript 0 end subscript right parenthesis over denominator e end fraction equals fraction numerator left parenthesis 3 plus 2.2 right parenthesis over denominator e end fraction e V almost equal to 0.9 V

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