Physics-
General
Easy

Question

In the rectangle, shown below, the two corners have charges q subscript 1 end subscript equals negative 5 mu C and q subscript 2 end subscript equals plus 2.0 mu C. The work done in moving a charge plus 3.0 mu C from B to A is (take 1 divided by 4 pi epsilon subscript 0 end subscript equals 1 0 to the power of 10 end exponent N minus m to the power of 2 end exponent rightwards arrow over short leftwards arrow divided by C to the power of 2 end exponent)

  1. 2.8 J    
  2. 3.5 J    
  3. 4.5 J    
  4. 5.5 J    

The correct answer is: 2.8 J


    Work done W equals 3 cross times 1 0 to the power of negative 6 end exponent left parenthesis V subscript A end subscript minus V subscript B end subscript right parenthesis semicolon where
    V subscript A end subscript equals 1 0 to the power of 10 end exponent open square brackets fraction numerator left parenthesis negative 5 cross times 1 0 to the power of negative 6 end exponent right parenthesis over denominator 15 cross times 1 0 to the power of negative 2 end exponent end fraction plus fraction numerator 2 cross times 1 0 to the power of negative 6 end exponent over denominator 5 cross times 1 0 to the power of negative 2 end exponent end fraction close square brackets equals fraction numerator 1 over denominator 15 end fraction cross times 1 0 to the power of 6 end exponent v o l t
    and V subscript B end subscript equals 1 0 to the power of 10 end exponent open square brackets fraction numerator left parenthesis 2 cross times 1 0 to the power of negative 6 end exponent right parenthesis over denominator 15 cross times 1 0 to the power of negative 2 end exponent end fraction minus fraction numerator 5 cross times 1 0 to the power of negative 6 end exponent over denominator 5 cross times 1 0 to the power of negative 2 end exponent end fraction close square brackets equals negative fraction numerator 13 over denominator 15 end fraction cross times 1 0 to the power of 6 end exponent v o l t
    \ W equals 3 cross times 1 0 to the power of negative 6 end exponent open square brackets fraction numerator 1 over denominator 15 end fraction cross times 1 0 to the power of 6 end exponent minus open parentheses negative fraction numerator 13 over denominator 15 end fraction cross times 1 0 to the power of 6 end exponent close parentheses close square brackets= 2.8 J

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