Have a query? Ask a Tutor!!

Access to best educators and exclusive paper discussions

Offsite Campus Turito Championship

Can’t find what you’re looking for?

Our tutors are from top schools around the world, and they are waiting for you 24/7, anytime, anywhere.

Homework- One to One Solutions
Understand concepts to solve better
Get your doubts solved instantly

Chemistry-

General

Easy

Question

Metals can be prevented from rusting by –

Connecting iron to more electropositive metal cathodic protection
Connecting iron to more electropositive metal anodic protection
Connecting iron to less electropositive metal anodic protection
Connecting iron to less electropositive metal cathodic protection

The correct answer is: Connecting iron to more electropositive metal cathodic protection

The process is called cathodic protection where iron acts as cathode and thus, not oxidised.

Related Questions to study

The thermodynamic efficiency of cell is given by –

The thermodynamic efficiency of cell is given by –

Chemistry-General

The following facts are available $table row cell 2 X to the power of minus end exponent plus Y subscript 2 end subscript rightwards arrow 2 Y to the power of minus end exponent plus X subscript 2 end subscript end cell row cell 2 W to the power of minus end exponent plus Y subscript 2 end subscript rightwards arrow text end text text N end text text o end text text end text text r end text text e end text text a end text text c end text text t end text text i end text text o end text text n end text text end text end cell row cell 2 Z to the power of minus end exponent plus X subscript 2 end subscript rightwards arrow 2 X to the power of minus end exponent plus Z subscript 2 end subscript end cell end table$ Which of the following is correct?

The following facts are available $table row cell 2 X to the power of minus end exponent plus Y subscript 2 end subscript rightwards arrow 2 Y to the power of minus end exponent plus X subscript 2 end subscript end cell row cell 2 W to the power of minus end exponent plus Y subscript 2 end subscript rightwards arrow text end text text N end text text o end text text end text text r end text text e end text text a end text text c end text text t end text text i end text text o end text text n end text text end text end cell row cell 2 Z to the power of minus end exponent plus X subscript 2 end subscript rightwards arrow 2 X to the power of minus end exponent plus Z subscript 2 end subscript end cell end table$ Which of the following is correct?

Chemistry-General

A standard hydrogen electrode has zero electrode potential because:

A standard hydrogen electrode has zero electrode potential because:

Chemistry-General

parallel

Given that $E subscript F e to the power of 3 plus end exponent divided by F e to the power of 2 plus end exponent end subscript equals negative 0.36 V$ and $E subscript F e to the power of 2 plus end exponent divided by F e end subscript equals negative 0.439 V$ respectively. Therefore value of $E to the power of ring operator end exponent F e to the power of 3 plus end exponent comma F e to the power of 2 plus end exponent divided by P t$ is :

Given that $E subscript F e to the power of 3 plus end exponent divided by F e to the power of 2 plus end exponent end subscript equals negative 0.36 V$ and $E subscript F e to the power of 2 plus end exponent divided by F e end subscript equals negative 0.439 V$ respectively. Therefore value of $E to the power of ring operator end exponent F e to the power of 3 plus end exponent comma F e to the power of 2 plus end exponent divided by P t$ is :

Chemistry-General

Given that $E subscript H subscript 2 end subscript O open vertical bar H subscript 2 end subscript close vertical bar P t end subscript equals 0$ at 298 K. The pressure of H₂(g) would be –

Given that $E subscript H subscript 2 end subscript O open vertical bar H subscript 2 end subscript close vertical bar P t end subscript equals 0$ at 298 K. The pressure of H₂(g) would be –

Chemistry-General

Two half cells have reduction potentials –0.76 V and – 0.13 V respectively. A galvanic cell is made from these two half cells. Which of the following statements is correct?

Two half cells have reduction potentials –0.76 V and – 0.13 V respectively. A galvanic cell is made from these two half cells. Which of the following statements is correct?

Chemistry-General

parallel

Given that Eº values of Ag⁺/Ag, K⁺/ K, Mg²⁺/ Mg and Cr³⁺/ Cr are 0.80V, –2.93V, –2.37V and –0.74V respectively. Therefore, the order for the reducing power of the metal is -

Given that Eº values of Ag⁺/Ag, K⁺/ K, Mg²⁺/ Mg and Cr³⁺/ Cr are 0.80V, –2.93V, –2.37V and –0.74V respectively. Therefore, the order for the reducing power of the metal is -

Chemistry-General

The standard potentials at 298 K for the following half reactions are as given
$table row cell Z n to the power of 2 plus end exponent left parenthesis a q right parenthesis plus 2 e to the power of minus end exponent rightwards harpoon over leftwards harpoon Z n left parenthesis s right parenthesis semicolon minus 0.762 V end cell row cell C r to the power of 3 plus end exponent left parenthesis a q right parenthesis plus 3 e to the power of minus end exponent rightwards harpoon over leftwards harpoon C r left parenthesis s right parenthesis semicolon minus 0.74 V end cell row cell 2 H to the power of plus end exponent left parenthesis a q right parenthesis plus 2 e to the power of minus end exponent rightwards harpoon over leftwards harpoon H subscript 2 end subscript left parenthesis g right parenthesis semicolon plus 0.00 V end cell row cell F e to the power of 3 plus end exponent left parenthesis a q right parenthesis plus e to the power of minus end exponent rightwards harpoon over leftwards harpoon F e to the power of 2 plus end exponent left parenthesis a q right parenthesis semicolon plus 0.77 V end cell end table$
Which of the following is the strongest reducing agent?

The standard potentials at 298 K for the following half reactions are as given
$table row cell Z n to the power of 2 plus end exponent left parenthesis a q right parenthesis plus 2 e to the power of minus end exponent rightwards harpoon over leftwards harpoon Z n left parenthesis s right parenthesis semicolon minus 0.762 V end cell row cell C r to the power of 3 plus end exponent left parenthesis a q right parenthesis plus 3 e to the power of minus end exponent rightwards harpoon over leftwards harpoon C r left parenthesis s right parenthesis semicolon minus 0.74 V end cell row cell 2 H to the power of plus end exponent left parenthesis a q right parenthesis plus 2 e to the power of minus end exponent rightwards harpoon over leftwards harpoon H subscript 2 end subscript left parenthesis g right parenthesis semicolon plus 0.00 V end cell row cell F e to the power of 3 plus end exponent left parenthesis a q right parenthesis plus e to the power of minus end exponent rightwards harpoon over leftwards harpoon F e to the power of 2 plus end exponent left parenthesis a q right parenthesis semicolon plus 0.77 V end cell end table$
Which of the following is the strongest reducing agent?

Chemistry-General

In which of the following is the cell the overall cell reaction is: $Z n plus H subscript 2 end subscript S O subscript 4 end subscript rightwards arrow Z n S O subscript 4 end subscript plus H subscript 2 end subscript$

In which of the following is the cell the overall cell reaction is: $Z n plus H subscript 2 end subscript S O subscript 4 end subscript rightwards arrow Z n S O subscript 4 end subscript plus H subscript 2 end subscript$

Chemistry-General

parallel

In which of the following electrochemical cell overall cell reaction is : $H g O left parenthesis s right parenthesis plus H subscript 2 end subscript left parenthesis g right parenthesis rightwards arrow H g left parenthesis l right parenthesis plus H subscript 2 end subscript O left parenthesis l right parenthesis$

In which of the following electrochemical cell overall cell reaction is : $H g O left parenthesis s right parenthesis plus H subscript 2 end subscript left parenthesis g right parenthesis rightwards arrow H g left parenthesis l right parenthesis plus H subscript 2 end subscript O left parenthesis l right parenthesis$

Chemistry-General

In which of the following cells net cell reaction is: $A g vertical line A g C l left parenthesis s right parenthesis vertical line K C l left parenthesis a q right parenthesis vertical line vertical line A g N O subscript 3 end subscript left parenthesis a q right parenthesis ∣ A g$

In which of the following cells net cell reaction is: $A g vertical line A g C l left parenthesis s right parenthesis vertical line K C l left parenthesis a q right parenthesis vertical line vertical line A g N O subscript 3 end subscript left parenthesis a q right parenthesis ∣ A g$

Chemistry-General

A lead shot of diameter 1mm falls through a long column of glycerin The variation of the velocity ‘v’ with distance covered (s) is represented by

A lead shot of diameter 1mm falls through a long column of glycerin The variation of the velocity ‘v’ with distance covered (s) is represented by

Physics-General

parallel

The graph shows the change ' $capital delta l$ ' in the length of a thin uniform wire used by the application of force ‘F’ at different temperatures T₁ and T₂ The variation suggests that

The graph shows the change ' $capital delta l$ ' in the length of a thin uniform wire used by the application of force ‘F’ at different temperatures T₁ and T₂ The variation suggests that

Physics-General

The load versus extension graph for four wires of same material is shown. The thinnest wire is represented by the line

The load versus extension graph for four wires of same material is shown. The thinnest wire is represented by the line

Physics-General

In given figure, a wire loop has been bent so that it has three segments: segment ab (a quarter circle), bc (a square corner), and ca (straight). Here are three choices for a magnetic field through the loop:

$text 1) end text stack B with rightwards arrow on top subscript 1 end subscript equals 3 stack i with hat on top plus 7 stack j with hat on top minus 5 t stack k with hat on top comma text 2) end text stack B with rightwards arrow on top subscript 2 end subscript equals 5 t stack i with hat on top minus 4 stack j with hat on top minus 15 stack k with hat on top comma text 3) end text stack B with rightwards arrow on top subscript 3 end subscript equals 2 stack i with hat on top minus 5 stack t with hat on top minus 12 stack k with hat on top$
Where $stack B with rightwards arrow on top$ is in milliteslas and t is in seconds. If the induced current in the loop due to $stack B with rightwards arrow on top subscript 1 end subscript comma stack B with rightwards arrow on top subscript 2 end subscript text end text$ and $stack B with rightwards arrow on top subscript 3 end subscript$ are $i subscript 1 end subscript comma i subscript 2 end subscript text and end text i subscript 3 end subscript$ respectively then

In given figure, a wire loop has been bent so that it has three segments: segment ab (a quarter circle), bc (a square corner), and ca (straight). Here are three choices for a magnetic field through the loop:

$text 1) end text stack B with rightwards arrow on top subscript 1 end subscript equals 3 stack i with hat on top plus 7 stack j with hat on top minus 5 t stack k with hat on top comma text 2) end text stack B with rightwards arrow on top subscript 2 end subscript equals 5 t stack i with hat on top minus 4 stack j with hat on top minus 15 stack k with hat on top comma text 3) end text stack B with rightwards arrow on top subscript 3 end subscript equals 2 stack i with hat on top minus 5 stack t with hat on top minus 12 stack k with hat on top$
Where $stack B with rightwards arrow on top$ is in milliteslas and t is in seconds. If the induced current in the loop due to $stack B with rightwards arrow on top subscript 1 end subscript comma stack B with rightwards arrow on top subscript 2 end subscript text end text$ and $stack B with rightwards arrow on top subscript 3 end subscript$ are $i subscript 1 end subscript comma i subscript 2 end subscript text and end text i subscript 3 end subscript$ respectively then

Physics-General

parallel

card img

With Turito Academy.

card img

With Turito Foundation.

card img

Get an Expert Advice From Turito.

Turito Academy

card img

With Turito Academy.

Test Prep

card img

With Turito Foundation.