Chemistry-
General
Easy
Question
Given that Eº values of Ag+/Ag, K+/ K, Mg2+/ Mg and Cr3+/ Cr are 0.80 V, –2.93 V, –2.37 V and –0.74 V respectively. Therefore, the order for the reducing power of the metal is -
- Ag > Cr > Mg > K
- Ag < Cr < Mg < K
- Ag > Cr > K > Mg
- Cr > Ag > Mg > K
The correct answer is: Ag < Cr < Mg < K
More the negative Eº value, larger the reducing power of the metal.
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