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Physics-

General

Easy

Question

On a planet a freely falling body takes 2 sec when it is dropped from a height of 8 m, the time period of simple pendulum of length 1 m on that planet is

3.14 sec
16.28 sec
1.57 sec
None of these

The correct answer is: 3.14 sec

On a planet, if a body dropped initial velocity (u = 0) from a height h and takes time t to reach the ground then $h equals fraction numerator 1 over denominator 2 end fraction g subscript P end subscript t to the power of 2 end exponent rightwards double arrow g subscript P end subscript equals fraction numerator 2 h over denominator t to the power of 2 end exponent end fraction equals fraction numerator 2 cross times 8 over denominator 4 end fraction equals 4 m divided by s to the power of 2 end exponent$
Using $T equals 2 pi square root of fraction numerator l over denominator g end fraction end root$ Þ $T equals 2 pi square root of fraction numerator 1 over denominator 4 end fraction end root equals pi equals 3.14$ sec.

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