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Physics-

General

Easy

Question

On bombarding $U to the power of 235 end exponent$ by slow neutrons, 200MeV energy is released. If the power output of atomic reactor is 1.6 MW, then the rate of fission will be

$5 \times 10^{22} s^{- 1}$
$5 \times 10^{16} s^{- 1}$
$8 \times 10^{16} s^{- 1}$
$20 \times 10^{16} s^{- 1}$

The correct answer is: $5 cross times blank 10 to the power of 16 end exponent s to the power of negative 1 end exponent$

Energy released on bombarding $U to the power of 235 end exponent$ by neutron=200 MeV
Power output of atomic reactor = 1.6 MW
$therefore$ Rate of fission= $fraction numerator 1.6 blank cross times blank 10 to the power of 6 end exponent over denominator 200 blank cross times blank 10 to the power of 6 end exponent cross times 1.6 blank cross times blank 10 to the power of negative 19 end exponent end fraction$
$equals blank 5 blank cross times blank 10 to the power of 16 end exponent s to the power of negative 1 end exponent$

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